Question

find the image of point (1,-2,3) in the plane 2x-3y+2z+3=0​

Answer 1

Answer:

let the points be ( 1,-2,3)

and the equation of the plane be 2x+3y+2z+3 = 0

now

using the two points formulae

A - x-1/2=y+2/3=z-3/2=k

well be getting the co ordinates of the points on A

now substitute the above points in the below plane to find k

2(2k+1) - 3(3k -2) + 2(2k + 3) +3 = 0

k = 17

now,

x = 2(17) + 1 = A

y = 3(17) - 2 = B

z = 2(17) + 3 = C

now equating it with its mirror one

A = -1 + x / 2,

B =2 + y /3

C = z-3 /2

To get x and y and z as your answer