Question

Find the image of the point (-3,1) in the line 2x-3y=4

Answer 1

Answer:

Step-by-step explanation:

the image of 2x-3y=4 is when point (-3,1)is

2(-3)-3(1)=4

-6-3=4

-13

Answer 2

Answer:

Let image of P is Q.

∴ PM = MQ & PQ ⊥ AB

Let Q is (h, k)

∴ M is h-1/2, k+2/2

It lies on 2x - 3y + 4 = 0

∴ 2 (h-1/2) - 3 (k + 2/2) + 4 = 0

Slope of PQ = k-2/h+1

PQ ⊥ AB

∴  k-2/h+1 x 2/3 = -1

Thus,

h=3/13

k=2/13

∴ Image of P(-1/2) is Q (3/13,2/13)

Aliter

The image of P (– 1, 2) about the line 2x – 3y + 4 = 0 is

x+1/2=y-2/-3 = -2(2(-1)-3(2)+4/2^2 + (-3)^2)

x+1/2=y-2/-3 = 8/13

= 13x + 13 = 16

= x = 3/13

& 13y - 26 = -24

y=2/13

∴ Image is 3/13,2/13

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Step-by-step explanation: