Question

Find the image of the point
(4, −7) with respect to −

15 pts pls answer​

Answer 1

Answer:

Correct answer is this

Let the equation of the L be y = mx + c Since O′ (–2, 6) is the image of the point O (4, 2) in line L = 0, the mid-point of OO′, i.e., (−2+42,6+22)(−2+42,6+22), i.e., (1, 4) will lie on the given line. Also, L ⊥ OO′, so Slope of L x Slope of OO′ = –1 ⇒ m x (6−2−2−4)(6−2−2−4)= -1 ⇒ m = −1−23−1−23 = 3232 ∴ Equation of L is y = 32x+c32x+c ∵ It passes through (1, 4) 4 = 3232 x 1 + c ⇒ c = 4 - 3232 = 52.52. ∴ Required equation is y = 32x32x + 5252 ⇒ 3x – 2y + 5 = 0 ∴ L = 3x – 2y + 5.Read more on Sarthaks.com - https://www.sarthaks.com/1017645/if-2-6-is-the-image-of-the-point-4-2-with-respect-to-the-line-l-0-then-l-is-equal-to

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