Question

Find the image of the point (−5, 8) with respect to y-axis

Answer 1

Answer:

(-5,-8)....

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Answer 2

$\underline{\boxed{\bold{Question}}}$  

↠ Find the image of the point (−5, 8) with respect to y-axis .

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$\underline{\boxed{\bold{Important\;Information}}}$  

❏ Image of a point is a co-ordinates of point that is located to same perpendicular distance from the given line.

❏ Reflection of a point about any arbitrary line : The image (h , k) of a point P (x₁ , y₁) about line ax + by + c = 0 is given by following formula :

$\boxed{ \bold {\red{:\leadsto \; \frac{h-x_1}{a} = \frac{k-y_1}{b} = -2(\frac{ax_1 + by_1 + c}{a^{2} +b^{2} } ) }}}$

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$\underline{\boxed{\bold{Given}}}$

↠ Equation of line : x = 0

↠ Point P(x₁ , y₁) = (-5 , 8)

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$\underline{\boxed{\bold{Answer}}}$

Let's Start  

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Let's use formula and solve this question !

$\boxed{ \bold {\blue{:\leadsto \; \frac{h-x_1}{a} = \frac{k-y_1}{b} = -2(\frac{ax_1 + by_1 + c}{a^{2} +b^{2} } ) }}}$

$:\implies \; \frac{h-x_1}{a} = \frac{k-y_1}{b} = -2(\frac{ax_1 + by_1 + c}{a^{2} +b^{2} } )$

$:\implies \; \frac{h-(-5)}{1} = \frac{k-8}{0} = -2(\frac{-5}{1 } )$

$\boxed{ \bold{:\implies \; \frac{h+5}{1} = \frac{k-8}{0} = -2(\frac{-5}{1 } ) }}$

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Now let's solve this equation for x-coordinate !

$\boxed{ \bold{:\implies \; \frac{h+5}{1} = -2(\frac{-5}{1 } ) }}$

$:\implies \; h + 5 = 10$

$:\implies \; h = 10 - 5$

$\boxed{\bold{\pink{:\implies \; h = 5 }}}$

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Now let's solve this equation for y-coordinate !

$\boxed{ \bold{:\implies \; \frac{k-8}{0} = -2(\frac{-5}{1 } ) }}$

$:\implies \; h - 8 = 0$

$:\implies \; h = 0 + 8$

$\boxed{ \bold{ \pink{:\implies \; h= 8}}}$

NOTE : Instead of trending term infinity as 0 is present denominator , take it to other side to multiply and make that side zero (0).

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$\boxed{\boxed{\bold{\therefore Image\; of \; Point\; P\; (-5,8) \; is \; (5,8) \; wrt.\; to \; y-axis }}}$

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Hope this helps u.../

【Brainly Advisor】