Find the image of the point (6, 2) in the line 2x + 3y – 5 = 0
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Step-by-step explanation:
L = 3x - 2y + 5 if (-2, 6) is the image of the point (4, 2) with respect to line L = 0
Step-by-step explanation:
(-2, 6) is the image of the point (4, 2) with
respect to line L = 0
Mid point of (-2, 6) & (4, 2) with lie on L
mid point = ( -2 + 4)/2 , ( 6 + 2)/2
= 1 , 4
Slope of (-2, 6) & (4, 2)
= (2 - 6)/(4 -(-2))
= -4/6
= - 2/3
Slope of L = 3/2
y = 3x/2 +c
1 , 4 lies on this line
=> 4 = 3/2 + c
=> c = 5/2
=> y = 3x/2 + 5/2
=> 2y = 3x + 5
=> 3x - 2y + 5 = 0
=> L = 3x - 2y + 5
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