Question

Find the imaginary roots of 4x² + 3x + 5 = 0.

Answer 1

HELLO DEAR,

4X²+3x+5=0


a=4

b=3

c=5

where discriminant


$d = \sqrt{ {b}^{2} { - 4ac} } = \sqrt{ {(3)}^{2} - 4 \times 4 \times 5} \\ = > \sqrt{9 - 80} = \sqrt{ - 71} = i \sqrt{71}$
WHERE

i=√(-1)


we know that:-

Quadratic formula ;-

for the value of x is

$x = \frac{( - (b )+ - \sqrt{ d} )}{2a} \\ = > x = \frac{ - (b )+ - \sqrt{ {b}^{2} - 4ac } }{2a} ....put \: the \: \: value \: of \: (d) \\ we \: get \\ = > x = \frac{ - (3 )+ - (i\sqrt{ 71 }) }{2 \times 4} \\ \\ take \: ( + sig.) \\ = > x = \frac{ - 3 + i \sqrt{71} }{8} \\ or \: \\ ( - )sig. \\ \\ x = \frac{ - 3 - i \sqrt{71} }{8}$
I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Step-by-step explanation:

hope it's helpful to you this attachment

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