Question

Find the incenter of the triangle formed by the following straight lines x=1,y=1,x+y=1​

Answer 1

Step-by-step explanation:

Correct option is

C

(

2

1

,

2

1

)

REF.Image

Let incentre be at (a,b)

OP = OQ = OR = radius

⇒(1−b)=(1−a)=

∣

∣

∣

∣

2

a+b−1

∣

∣

∣

∣

⇒(a−1)

2

=(b−1)

2

⇒a=b

⇒1−a=

2

2a−1

⇒2a−1=

2

−

2

a

⇒a=

2

(

2

+1)

2

+1

=

2

1

⇒(C)

solution