Question

find the inclination of line x+y+1=0 with the possitive x axis​

Answer 1

$\underline{\bold{Answer:-}}$

135°

$\underline{\bold{Explanation:-}}$

Given, equation is x+y+1 = 0

As we know,

Slope(m) of a equation, which is in the form ax+by+c=0 is-

$\dfrac{-a}{b}$

In the equation

a = 1, b = 1

Now

Slope(m) = $\dfrac{-1}{1}$

m = -1 -----(1)

We know that

m = tanΦ -------(2)

From (1) and 2

tanΦ = -1

Φ = 135° or $\dfrac{3 \pi}{4}$

Answer 2

Answer:

Step-by-step explanation:

x+y+1=0

y=-x-1

m=-1

m=tanФ

tanФ=-1

Ф=tan^-1(-1)