find the inclination of the line x+√3y+6=0
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x+root3y+6=0
root3y=-x-6
y= -x/root3 -6/root3
y= (-1/root3)x +(-6)
it is in form of , y= MX +c
where, M= tantheta = slope
so , inclination of line = M = -1/root3
M= tantheta = -1/root3
tan theta = tan (pie/3)
theta = pie/3 or 30 degree
hope it help you dear....
root3y=-x-6
y= -x/root3 -6/root3
y= (-1/root3)x +(-6)
it is in form of , y= MX +c
where, M= tantheta = slope
so , inclination of line = M = -1/root3
M= tantheta = -1/root3
tan theta = tan (pie/3)
theta = pie/3 or 30 degree
hope it help you dear....
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i hope this will help you.
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