Question

find the increase in k.e of a body of mass 0.5kg , then its speed increases from 4m/s to 8m/s

Answer 1

Given

• Mass of the body = 0.5 Kg
• Velocity (V₁) = 4 m/s
• Velocity (V₂) = 8 m/s

☯ Speed increases from 4 m/s to 8 m/s

To find

• Increase in Kinetic energy

Solution

• K.E₁ = 1/2 mv²
• K.E₁ = 1/2 × 0.5 × 4²
• K.E₁ = 4

☯ Kinetic energy (K₁) = 4 J

• K.E₂ = 1/2 mv²
• K.E₂ = 1/2 × 0.5 × 8²
• K.E₂ = 16

☯ Kinetic energy (K₂) = 16 J

⋆ Increase in Kinetic energy = (K₂) - (K₁)

⋆ Increase in Kinetic energy = 16 J - 4 J

⋆ Increase in Kinetic energy = 12 J (Joules)

Answer 2

Answer:

49 N−s

Change in momentum = force × time

=mg×time

=0.5×9.8×10

=49Kgm/S

(g=9.8m/s

2

)

Explanation:

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