Find the increase in kinetic energy body of mass 500 when increase speed 2/ms to 3/ms
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KE initial = 1/2mu² = 1/2*(500)*(2)² = 1/2*500"4 = 1000 J
KE final = 1/2mv² = 1/2*(500)(3)² = 250*9 = 2250 J
∆KE = KE final - KE initial = 2250-1000 = 1250J
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