Question

find the increase in kinetic energy of a body of mass 600g when its speed increases from 2m s^-1 to 5m s^-1

Answer 1

Answer:

I'm unable to find more

Answer 2

NAMAASTE..

◀◀◀ Hey ▶▶▶

Your solution ⤵⤵⤵

Kinetic energy = mv²/2

M= 0 .5 kg

when v= 2

kinetic \: energy \: \\ = > \frac{1}{2} \times 0.5 \times 2 \times 2 = 1 \: joule

When V = 4

ke \: = \frac{1}{2} \times 0.5 \times 4 \times 4</em></p><p><em>=</em><em>></em><em> </em><em>\</em><em>:</em><em>4 \: joules

Difference between Kinetic energy

=> 4 - 1= 3 joules

✨✨✨ Hope it helps ✨✨✨

❇❇❇ Thank U ❇❇❇