Find the increase in pressure required to decrease volume of Mercury by 0.001%
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Bulk modulus =p÷(-∆v/v) here bulk modulus of Hg is 2.8×10^10 N/m^2 and decrease in volume (in %) = -∆v/v × 100 and decrease in volume is 0.001% put value,, 0 .001=- ∆v/v×100 and then -∆v/v is 0.00001 means 10^-5 then putting the value in bulk modulus formula 2.8×10^10=p÷10^-5 then p= 2.8×10^5 N/m^2 ans
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