Find the increase in the kinetic energy of a body of mass 750g when the speed increases from 6m/s to 8m/s. *
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Answer:
M=750g(0.75kg)
v1=6m/s
K.E1=1/2mv1^2
1/2×0.75×6*6
1/2×0.75×36
13.5J
V2=8m/s
K.E2=1/2mv1^2
1/2×0.75×8*8
1/2×0.75×64
24J
Increase in K.E.
K.E2-K.E1=24-13.5
10.5J
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