Find the indicated term of each term of each geometric sequence
a⁵=, a¹⁰=48 find a¹ and r
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Find the 7th term for the geometric sequence in which a2=24 and a5=3 .
Substitute 24 for a2 and 3 for a5 in the formula
an=a1⋅rn−1 .
a2=a1⋅r2−1→24=a1ra5=a1⋅r5−1→ 3=a1r4
Solve the firstequation for a1 : a1=24r
Substitute this expression for a1 in the second equation and solve for r .
3=24r⋅r43=24r318=r3 so r=12
Substitute for r in the first equation and solve for a1 .
24=a1(12)48=a1
Now use the formula to find a7 .
a7=48(12)7−1=48⋅164=34
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