Question

find the inductance of a coil in which a current of 0. 2A increasing at the rate of 0. 4. A per second represents a power of 0. 4watt.
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Answer 1

Answer:

Explanation:

Given :

• Correct through wire (i) = 0.2A
• Rate of increase of current (di/dt) = 0.4A/s
• Power flow of inductor (P) = 0.4W

To Find :

• The inductance of a coil, L

Solution :

★Inductance of a coil,

Formula of inductance of a coil is given as ;

$\boxed{\green{\sf \: L = \cfrac{P}{i \: \times \: \cfrac{di}{dt} }}}$

Now,

$\implies \sf \: L = \cfrac{0.4}{0.2 \times 0.4} \\ \\ \implies \sf \: L = \cfrac{0.4}{0.08} \\ \\ \implies\boxed{ \sf \red{L = 5H}}$

Answer 2

$\Large \mathfrak{ \color{deepskyblue}{Given : }}$

• Correct through wire (i) = 0.2A
• Rate of increase of current (di/dt) = 0.4A/s
• Power flow of inductor (P) = 0.4W

$\Large \mathfrak{ \orange{To Find : }}$

• The inductance of a coil, L.

$\Large \mathfrak{ \pink{Solution :}}$

$\sf{\underline{ \blue{Formula \: of inductance of a coil : - }}}</p><p>$

$\boxed{ \orange{\sf \: L = \cfrac{P}{i \: \times \: \cfrac{di}{dt}}}}</p><p>$

Now,

$\begin{gathered}{ \green{ \implies \sf \: L = \cfrac{0.4}{0.2 \times 0.4} }}\\ \\{ \green{ \implies \sf \: L = \cfrac{0.4}{0.08}}} \\ \\{ \red{ \implies\boxed{ \sf \red{L = 5H}}}}\end{gathered}$