Find the initial momentum of electron if the momentum of electron is changed by Pm and the De Broglie wavelength associated with it changes by 0.50%.
Anonymous:
changed By what Pm?
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answer is 400p∘
λ∼1pλ∼1p⇒Δpp=−Δλλ⇒Δpp=−Δλλ⇒|Δpp|=|Δλλ|⇒|Δpp|=|Δλλ|⇒p∘p=0.25100=1400⇒p∘p=0.25100=1400⇒p=400p∘
λ∼1pλ∼1p⇒Δpp=−Δλλ⇒Δpp=−Δλλ⇒|Δpp|=|Δλλ|⇒|Δpp|=|Δλλ|⇒p∘p=0.25100=1400⇒p∘p=0.25100=1400⇒p=400p∘
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As You Know ,
De Brogli Equation :
λ = h/mv
λ = h/P....(1)
Let P0 be the initial Momentum and P is the decrease in momentum .
When wavelength changed by 0.5%
λ + 0.5λ/100 = h/P0-P
100.5λ/100 = h/P0-P----(2)
By 1 and 2
P0 = 1.99P
De Brogli Equation :
λ = h/mv
λ = h/P....(1)
Let P0 be the initial Momentum and P is the decrease in momentum .
When wavelength changed by 0.5%
λ + 0.5λ/100 = h/P0-P
100.5λ/100 = h/P0-P----(2)
By 1 and 2
P0 = 1.99P
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