Question

find the initial velocity and acceleration of a body if distance traveled by that body in nth second is (5.96+ 0.08n)metre?​

Answer 1

Answer: acceleration =.08m/s² and u = 6 m/s

Explanation:S nth =u +a/2 (2n-1)

5.96+.08n = u +a/2 (2n-1)

=u+ an -a/2

5.96 +.08n = (u - a/2) + an

By comparing

U- a/2 = 5.96 (no 1)

an= .08n ( n has been cancelled)

a = .08m/s²

From no 1

U- a/2 = 5.96

U - .08/2 = 5.96

U- .04 = 5.96

U = 5.96+ .04

= 6m/s

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