find the initial velocity of a bike which is stopped in 10 s by applying brakes. The retardation due to brakes is 2.5m/s^2
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15m/s i think...is it a right answer if yes i can explain if i can't
kinjal1567:
i feel its 25m/s^2
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Hi i'm Ritam and i hope that this is correct
v=final velocity =0.
u=initial velocity
a=acceleration
t=time = 10 s
v=u+at
here it is retardation and therfore a is taken as -2.5 m/s2
therefore the equation becomes
0=u-2.5*10.
u-25=0. u=25 m/s
i hope this is the correct answer.
Hopw this helps you and you get it.
v=final velocity =0.
u=initial velocity
a=acceleration
t=time = 10 s
v=u+at
here it is retardation and therfore a is taken as -2.5 m/s2
therefore the equation becomes
0=u-2.5*10.
u-25=0. u=25 m/s
i hope this is the correct answer.
Hopw this helps you and you get it.
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