Find the initial velocity of a car that is stopped in 10 second by applying brakes retardation due to break is 2.5 M per second square
Answers
Answered by
2
hey your ans is here
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u=?
v=0(since it comes to rest after moving a distance)
t=10
r=2.5 so acceleration will be -2.5
a=-2.5
now apply the formula
a=v-u/t
-2.5=0-u/10
-2.5×10=-u
u(initial velocity)=25m/s
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:-)
---------
u=?
v=0(since it comes to rest after moving a distance)
t=10
r=2.5 so acceleration will be -2.5
a=-2.5
now apply the formula
a=v-u/t
-2.5=0-u/10
-2.5×10=-u
u(initial velocity)=25m/s
--------
:-)
Answered by
1
u=0
v=0
t=0
r=2.5
a=-2.5
by applying the third formula,
a=v-u/t
=-2.5×10=-u
u=(initial velocity)=25m/s (Ans)
v=0
t=0
r=2.5
a=-2.5
by applying the third formula,
a=v-u/t
=-2.5×10=-u
u=(initial velocity)=25m/s (Ans)
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