Find the initial velocity of a car that is stopped in 10 s by applying brakes.
Retardation due to brakes is 2.5m/s^2
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a =( - 2.5 m / s ^2 )
( As there is retardation so acceleration will be negative )
time = t = 10s
final velocity = v = 0 m / s
( as car has been stopped so final velocity will be 0 )
Using 3rd equation of motion =
v = u + at
0 = u +( - 2.5 * 10 )
0 + 25 = u
25 = u = intial velocity
( As there is retardation so acceleration will be negative )
time = t = 10s
final velocity = v = 0 m / s
( as car has been stopped so final velocity will be 0 )
Using 3rd equation of motion =
v = u + at
0 = u +( - 2.5 * 10 )
0 + 25 = u
25 = u = intial velocity
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