find the initial velocity of a car that is stopped in 10s by applying breaks. retardation due to breaks is 2.5ms-^2
Answers
Answered by
16
ANSWER :
Given :
▪ Stopping time = 10s
▪ Retardation of car = 2.5m/s^2
To Find :
▪ Initial velocity of car.
Formula Derivation :
✏ This question is completely based on concept of stopping (reaction) time.
✒ v = u + at
✒ 0 = u + (-a)t
✒ u = at
✒ t = u/a
- t denotes reaction time
- u denotes initial velocity
- a denotes retardation
Calculation :
→ t = u/a
→ u = at
→ u = 2.5 × 10
→ u = 25m/s
Answered by
3
Given:
★ Stopping time (t) = 10 seconds
★ Acceleration (a) = -2.5 m/s²
★ Final Velocity (v) = 0 [As brakes are applied]
To Find :
• Initial Velocity (u)
Some important Formulae :
→ v = u + at
→ s = ut + 1/2at²
→ 2as = v² - u²
Solution:
By using the formula,
v = u + at
0 = u + (- 2.5)×10
0 = u - 2.5×10
0 = u - 25
25 = u
Therefore, initial velocity of the car after applying breaks is 25 m/s .
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