find the initial velocity of a car which is a stopped in 10 seconds by applying brakes. the retardation due to break is 2.5 M per second square
Answers
Answered by
337
let final velocity be o and initial velocity be u
time = 10 sec
acceleration = -2.5m/s2
according to first formula
v = u + at
where v = 0
u = ?
a = -2.5m/s2
t = 10 sec
v = u + at
0 = u + (-2.5) * 10
0 = u - 25
u = 25 m/s
time = 10 sec
acceleration = -2.5m/s2
according to first formula
v = u + at
where v = 0
u = ?
a = -2.5m/s2
t = 10 sec
v = u + at
0 = u + (-2.5) * 10
0 = u - 25
u = 25 m/s
Answered by
100
initial velocity=?
final velocity=0
time=10
accelaration=-2.5m/s2
a=v-u/t
-2.5=0-u/10
-2.5=-u/10
-2.5*10=-u
-25=-u
25=u
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