Question

find the initial velocity of a car which is stopped in 10 seconds by applying brakes retardation due to brakesvis 2.5 m/s²​

Answer 1

Answer:

25 m/s

Explanation:

v = u + at

We know that the car is finally stopped

∴ v = 0    t = 10s

The accelation was opposite in direction of motion

∴a = -2.5 m/s²

0 = u + (-2.5)(10)

   = u + (-25)

    = u - 25

u = 0+25

u = 25m/s

Hope it helps and plz follow

Answer 2

Answer:

25m/s

Explanation:

v=u+at

v=0,u=?,a= -2.5,t=10.

0=u-2.5(10)

u=25m/s