Question

Find the initial velocity of a car which is stopped in 10 seconds by applying break . The retardation due to breaks in 2.5 m/sec.2

Answer 1

Answer:

u=?

v=0

t=10s

a=-2.5m/s

u=v-at

=0-(-2.5)×10

=25

Answer 2

Explanation:

Answer ⤵️

Initial velocity, u=?

Final velocity, v=0m/s (car is stopped)

Acceleration, a=−2.5m/s²(negative because it is retardation)

Time, t=10s

Use the relation of the first equation of motion:

v=u+at

0=u+(−2.5)×10

u=25m/s

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