Find the initial velocity of a car which is stopped in 10 s by appling breaks . The retardation due to breaks is 2.5 m/s square
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we know v=u-at.v=final velocity=0u=initial velocity=?a=retardation=2.5t=time=10so 0=u-2.5(10)⇒u=25mps
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the initial velocity is 25m/s . please mark me brainliest
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