Find the initial velocity of a car which is stopped in 10s by applying brakes. The retardation due to brakes is 2.5 m/s.
Answers
Answered by
9
a = v-u/t
-25/10 = 0-u/10
-u = -25
u = 25
-25/10 = 0-u/10
-u = -25
u = 25
Answered by
5
Answer:
Initial velocity = 25 m/s
Explanation:
Time = 10 sec, Retardation = -2.5 m/s^2 and Final velocity = 0 m/s
v = u + at (First Equation Of Motion)
0 = u + (-2.5)(10)
0 = u - 25.0
-u = -25.0
u = 25 m/s
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