Find the initial velocity of a car which is stopped in 4 seconds by applying brakes.The retardation due to brakes is 5m/s square.
Answers
Answered by
2
here is your answer
v=0
u=?
a=5m/s square
t= 4seconds
a= v-u/t
5=0-u/4
5×4=-u
u=-20m/s
so,
initial velocity=-20m/s
hope it helps you.
v=0
u=?
a=5m/s square
t= 4seconds
a= v-u/t
5=0-u/4
5×4=-u
u=-20m/s
so,
initial velocity=-20m/s
hope it helps you.
zonunmawii:
then please let me see your solve
ok
v=0, u=?, t=4 second, a=-5m/s
then, a=v-u/s
-5=0-u/4
-u=4*-5
u= 20m/s
thank you very much i know how to solve now .......thnks.....☺
most welcome dear
there is no my mistake, because acceleration is positive in the question.
Answered by
2
Explanation:
Answer ⤵️
Initial velocity, u=?
Final velocity, v=0m/s (car is stopped)
Acceleration, a=−2.5m/s²(negative because it is retardation)
Time, t=10s
Use the relation of the first equation of motion:
v=u+at
0=u+(−2.5)×10
u=25m/s
xXitzSweetMelodyXx
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