Find the initial velocity of a car which stops in 10seconds after applying brakes at the rate of 2m/s²
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Answer:
Initial velocityGiven: Final velocity=0Time=10 secAcceleration= -2.5 m/s^2 (Negative sign as it is retardation)Using:a=v-u/t-2.5=0-u/10-2.5=-u/10-2.5*10=-u-25=-u25=u Therefore, Initial velocity is 25 m/s.
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Answer:
Negative acceleration is retardation so,
a=-2m/s^2
the car applies brakes so the final velocity(v) is =0m/s
t=10s
a=v-u/t
-2=0-u/10
-20=0-u
u=0+20
u=20m/s
initial velocity is 20m/s
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