Question

find the initial velocity of a train wheel stopped in 15 seconds the retardation producing the train is 1.5 metre per second square​

Answer 1

Solution :-

Given,

V = 0 m/s
T = 15 s
a = -1.5 metre second square

Using, V = u+ at,

We get,

$0 = u + ( - 1.5) + \times 15 \\ \\ 0 = u - 1.5 \times 15 \ \\ \\ u = 22.5$


Thanks!!

Answer 2

Answer:

Explanation:

Intial Velocity (u)=um/s

A train is stopped after sometime thus

Final velocity (v)=0

Retardation=1.5m/s^2

Time (t)=15seconds

Using formula of retradation

Retardation=(u-v)/t

1.5=(u-0)/15

22.5=u-0

Thus ,u=22.5m/s this is your answer