Question

Find the initial velocity of a train which is stopped in 20s by applying breaks is 1.5m/s²?​

Answer 1

Answer:

30m/s

Explanation:

v=u-at

0=u-at

u=at

u=1.5*20

u=30m/s

so initial velocity is 30m/s

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Answer 2

Given

• Time taken (t) = 20s
• Final velocity (v) = 0
• Acceleration (a) = - 1.5m/s²

To find

• Initial velocity = ?

Solution

As we know that

→ v = u + at {First equation of motion}

→ 0 = u - 1.5 × 20

→ 0 = u - 30

→ u = 30m/s

Hence,

• Initial velocity of train is 30m/s

Extra Information

• Force = mass × Acceleration
• s = ut + ½ at² {Second equation of motion}
• v² = u² + 2as {third equation of motion}
• Pressure = Force/Area