Question

Find the instantaneous acceleration of a particle when v= t^2 i + t j - 2k. Use a= dv/dt by showing each steps.​

Answer 1

$= = >$

☑ instantaneous acceleration

= delta v / delta t

a = dv / dt

☑ As we have given

v = t^2 i + t j - 2k

dv /dt = d / dt(t^2i + t j - 2k)

= 2ti+ d/dx(tj) - d/dx(2k)

= 2ti + j

☑ therefor instantaneous acceleration

is

$\boxed{\textbf{\large{2ti + j}}}$

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Derivative of terms

1)derivative of x ➡ 1

2)derivative of constants ( 1, 2 ,3 , k)

➡ 0

3)derivative of x^(n) ➡ n(x)^(n-1)