Question

find the integral of √1+x√1+(x+1)√1+(x+2)(x+4) dx​

Answer 1

Step-by-step explanation:

I=∫(x2+1)x4+1x2−1dx=∫(x+x1)x2+x211−x21dx

Substituting t=x+x1⇒dt=(1−x21)dx, we get

I=∫tt2−2dt=∫t2t2−2tdt

Again substituting y2=t2−2, we get

I=∫(y2+2)yydy=