Question

find the integral of 3x^2/1+x^3​

Answer 1

Answer:

log ( 1 + x^3)

Step-by-step explanation:

Answer 2

Concept:

In arithmetic, an integral lends numerical values to curves to represent notions like volume, area, and movement that result from combining infinitesimally small amounts of data. Integration is the action of locating integrals. In mathematics, integration is a technique for combining or adding the parts to arrive at the total. It is a form of differentiation in reverse where we break down functions into their component elements. This technique is employed to determine the accumulation on a sizable scale.

Given:

Here the equation given to us is $3x^2/1+x^3$.

Find:

We have to find the integral of the above equation.

Solution:

According to the question,

$I=\int\ ({3x^2/1+x^3} )\, dx$

$u=1+x^3\\du=3x^2$

$dx=du/3x^2$

$I=\int\ du/u\\=log u\\=log(1+x^3)$

Hence, the integral of the equation is $log(1+x^3)$.

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