find the integral roots of the polynomial
f(x)=x³+6x²+(11x)+6
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We choose x = -2 by hit and trial method.
So, f (x) = x³ + 6 x² + 11 x + 6
f (-2) = (-2)³ + 6 × (-2)² + 11 × -2 + 6
= -8 + 24 - 22 + 6
= -2 + 2
= 0
So, ( x + 2 ) is a roots/factors/zero of given polynomial.
So, f (x) = x³ + 6 x² + 11 x + 6
f (-2) = (-2)³ + 6 × (-2)² + 11 × -2 + 6
= -8 + 24 - 22 + 6
= -2 + 2
= 0
So, ( x + 2 ) is a roots/factors/zero of given polynomial.
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