Question

find the integral : sec^2x/cosec^2x

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

∫(sec2x​/cosec2x)dx

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∫(1/cos​​2x)/(1/sin2x)dx

∫(1/cos​2sin) . (sin2x/1)dx

∫tan2x dx

∫(sec2x-1) dx

tanx - x + c