Question

Find the integral value of n, such
that 3²(n+1) has zero at its
units digit.​

Answer 1

Answer:

n = 0

Step-by-step explanation:

: 3²(n+1)

: 9(n+1)

: 9n+9

: n = 9/9

: n = 0

hence, the value n is 0.