Question

Find the integral zero of 3y^4 - 4y^3 + 4y^2 - 4y + 1.

Answer 1

$3y^4 - 4y^3 + 4y^2 - 4y + 1$

$(y - 1)(3 {y}^{3} - {y}^{2} + 3y - 1)$

$(y - 1)(3y - 1)( {y}^{2} + 1)$