Question

find the integral zeroes of polynomial x³+3x²-x-3​

Answer 1

Answer:

1

Step-by-step explanation:

p(x)=x³+3x²-x-3​

p(1)=(1)³+3(1)²-1-3​

     =1+3-1-3

     =0

Therefore, 1 is the zero of the given polynomial

Answer 2

Answer:

x=1

Step-by-step explanation:

Let x=1

x³+3x²-x-3

(1)³+3(1)²-(1)-3

1+3-1-3

0

Therefore, 1 is the zero of the given polynomial.

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