Question

Find the integral zeroes of the polynomial g(x) = x3+5x2+2x−8.

Answer 1

Answer:

all the zeroes of the polynomial are = -4 , -2 , 1

solution

by hit and trial method

we put x = 1

${x}^{3} + 5 {x}^{2} + 2x - 8 = 0 \\ put \: x = 1 \\ 1 + 5 + 2 - 8 = 0$

now,

g(x)= x-1

and

p(x) = x^3 + 5x^2 +2x -8

on dividing p(x) by g(x)

we get x^2 +6x+8 as a quotient

and

by solving this we will get remaining two zeroes