Question

Find the integral zeroes of the polynomial p(x)=x^3-2x^2+x+4

Answer 1

hey bro!
here ur solution:

put the factor of 4 is -1 in eq
then

==>
$= > ( - 1 {)}^{3} - 2( - 1 {)}^{2} - 1 + 4 = 0 \\ \\ = > - 1 - 2 - 1 + 4 = 0 \\ \\ = > - 4 + 4 = 0 \\ \\ = > 0 = 0 \\ \\ its \: clear \: that \: x + 1 \: is \: a \: factor \\ \: of \: the \: eq \\ \\ now$

x^2(X+1) -3x(X+1)+4(x+1)

(X+1)( x^2-3x +4)