Math, asked by jatin00003, 1 month ago

find the integral zeros of 4x³+20x²-x-5​

Answers

Answered by jjasmeen012
1

Answer:

e steps

Step by Step Solution

Step by step solution :

STEP1:Equation at the end of step 1

(((4 • (x3)) - (22•5x2)) + x) - 5 = 0

STEP 2 :

Equation at the end of step2:

((22x3 - (22•5x2)) + x) - 5 = 0

STEP3:Checking for a perfect cube

 3.1    4x3-20x2+x-5  is not a perfect cube

Trying to factor by pulling out :

 3.2      Factoring:  4x3-20x2+x-5 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  x-5 

Group 2:  4x3-20x2 

Pull out from each group separately :

Group 1:   (x-5) • (1)

Group 2:   (x-5) • (4x2)

               -------------------

Add up the two groups :

               (x-5)  •  (4x2+1) 

Which is the desired factorization

Polynomial Roots Calculator :

 3.3    Find roots (zeroes) of :       F(x) = 4x2+1

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  4  and the Trailing Constant is  1.

 The factor(s) are:

of the Leading Coefficient :  1,2 ,4

 of the Trailing Constant :  1

 Let us test ....  P  Q  P/Q  F(P/Q)   Divisor     -1     1      -1.00      5.00        -1     2      -0.50      2.00        -1     4      -0.25      1.25        1     1      1.00      5.00        1     2      0.50      2.00        1     4      0.25      1.25   

Polynomial Roots Calculator found no rational roots

Equation at the end of step3:

(4x2 + 1) • (x - 5) = 0

STEP4:Theory - Roots of a product

 4.1    A product of several terms equals zero. 

 When a product of two or more terms equals zero, then at least one of the terms must be zero. 

 We shall now solve each term = 0 separately 

 In other words, we are going to solve as many equations as there are terms in the product 

 Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

 4.2      Solve  :    4x2+1 = 0 

 Subtract  1  from both sides of the equation : 

                      4x2 = -1

Divide both sides of the equation by 4:

                     x2 = -1/4 = -0.250

 

 When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                      x  =  ± √ -1/4  

 In Math,  i  is called the imaginary unit. It satisfies   i2  =-1. Both   i   and   -i   are the square roots of   -1 

Accordingly,  √ -1/4  =

                    √ -1• 1/4   =

                    √ -1 •√  1/4   =

                    i •  √ 1/4

The equation has no real solutions. It has 2 imaginary, or complex solutions.

                      x=  0.0000 + 0.5000 i 

                      x=  0.0000 - 0.5000 i 

Solving a Single Variable Equation:

 4.3      Solve  :    x-5 = 0 

 Add  5  to both sides of the equation : 

                      x = 5

Three solutions were found :

 x = 5

  x=  0.0000 - 0.5000 i 

  x=  0.0000 + 0.5000 i 

Step-by-step explanation:

I hope its help you

Answered by indain1981
0

your answer is in the above picture

and one more thing! in my notebook there is y instead of x.. but the question is all same!

hope it helps...

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