Question

Find the integrals of the function: $sin^{-1} (cos\ x)$

Answer 1

Answer:

Step-by-step explanation:

$concept;\\\\sin^{-1}(sinx)=x\\\\Now,\\\\\int{sin^{-1}(cosx)}\:dx\\\\=\int{sin^{-1}(sin(\frac{\pi}{2}-x))}\:dx\\\\=\int{(\frac{\pi}{2}-x)}\:dx\\\\=\frac{\pi}{2}x-\frac{x^2}{2}+c$