find the integrals of the functions 1-cos x/1+cos x
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Answer:
as we know
1-cosx=2(sin(x/2)^2)
and 1+cosx=2(cos(x/2)^2)
so 1-cosx/1+cosx=tan[(x/2)]^2
=(sec(x/2)^2)-1
taking integration both sides , we have
=2tan(x/2)-x
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