Math, asked by THEmultipleTHANKER, 1 month ago

Find the integrals (primitives):

\sf \displaystyle\int \frac{\sin 4x}{\cos 2x}\ dx

Answers

Answered by arunpatodi18
3

Answer:

cos(x2) dx = ∫ cos u du = sin u + C = sin(x2) + C. ... Find the antiderivatives or evaluate the definite integral in each problem. 1. ... + 316 (x + sin 4x. 4 ). + C.

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Answered by Ehsanul885
3

\sf \displaystyle\int \frac{\sin 4x}{\cos 2x}\ dx.

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