Question

Find the integrating factor for the linear differential equation .

( 1+X²)dy/DX + xy = 0
​

Answer 1

Step-by-step explanation:

Correct option is B

1−x

(1−x

2

)

dx

dy

−xy=1

⇒

dx

dy

+

1−x

2

−xy

=

1−x

2

1

Here, P(x)=−

1−x

2

x

and Q(x)=

1−x

2

1

Then,

I.F=e

∫P(x)dx

=e

2

1

∫

1−x

2

−2x

dx

=e

2

1

log(−x

2

+1)

=

−x

2

+1=

1−x

2