Question

find the integration ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

            16 / 3

Step-by-step explanation:

$\displaystyle\ \ \ \int_0^2\int_0^1 4x^2y\,dy\,dx\\\\= 4\left(\int_0^2x^2\,dx\right)\left(\int_0^1y\,dy\right)\\\\= 4\bigl[\tfrac13x^3\bigr]_0^2\times\bigl[\tfrac12y^2\bigr]_0^1\\\\= 4\bigl(\tfrac83-0\bigr)\bigl(\tfrac12-0\bigr)\\\\=4\times\tfrac83\times\tfrac12\\\\=\tfrac{16}{3}$