Math, asked by nahmednida7020, 11 months ago

Find the Integration Of 1/X

Answers

Answered by Anonymous
0

Step-by-step explanation:

Integration of 1/x

= logx

Answered by mishalkiranr
0

Answer:

 log( |x| )

Step-by-step explanation:

Hear integral of x^n is x^n+1/n+1

Given integral 1/x=x^-1

By above formula we get

 \frac{ {x}^{ - 1 + 1} }{  - 1 + 1} \\  =  \frac{ {x}^{0} }{0}  \\ when \: 0 \: is \: in \: denomenator \: it \: is \\ undifinied

To avoid this problem we have an additional formula i.e

integral \: of {x}^{ - 1} with \: respect \: to \: dx \\  =  log |x|

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