Question

find the integration of sin^2 x.dx
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Answer 1

Hope this help.......

Answer 2

Step-by-step explanation:

$Given:\int sin^2(x) dx$

$=\int\frac{1-cos2x}{2}dx$

$=\frac{1}{2}\int1-cos(2x) dx$

$=\frac{1}{2}(\int 1 dx-\int cos (2x)) dx$

$=\frac{1}{2}(x-\frac{1}{2} sin(2x))$

$=\boxed{\frac{1}{2}x - \frac{1}{4}sin(2x) + C}$

Hope it helps!