Question

find the intercept cut off by the line 3x+4y-10=0 on coordinate axis​

Answer 1

EXPLANATION.

Intercept cut off by the line → 3x + 4y - 10 = 0

on coordinate axis.

Let we assume that Intercept of point A lies

on the x - axis we get,

Put the value of y = 0 in given equation

we get,

→ 3x + 4(0) - 10 = 0.

→ 3x - 10 = 0.

→ x = 10/3.

→ Coordinate points of X - axis are

( 10/3,0).

Let we assume that intercept of point B lies

on the y - axis we get,

Put the value of x = 0 in the given equation

we get,

→ 3(0) + 4y - 10 = 0.

→ 0 + 4y - 10 = 0.

→ 4y = 10.

→ y = 5/2.

→ Coordinate points of Y - axis are

( 0,5/2).

More information.

We can also find Distance between both the

axis.

By using the Distance Formula.

$\sf \: \implies \: \sqrt{(x_{1} - x_{2}) {}^{2} + ( y_{1} - y_{2}) {}^{2} }$

→ √ ( 10/3 - 0 )² + ( 0 - 5/2)².

→ √ 100/9 + 25/4.

→ √ 400 + 225 / 36.

→ √ 625/36

→ 25/6.

Distance between both axis = 25/6.